Post by Eugene 2.0 on Sept 17, 2023 11:31:03 GMT
Here's one of the simplest and the most widespread the NOT element implementation:
en.m.wikipedia.org/wiki/Inverter_(logic_gate)#/media/File%3ARTL_NOT_Gate.svg
I don't know whether this analysis is correct, but I've made it in two conceptual views:
* there are three circuits:
a) V5+ °——— ———°V?
b) V5+ °——— ——.\_._/Q ———° V0
c) V5+ °——— ———|<→Q ———° V?
d) V5+ °——— ———|< Q ————° V0
or as it is on the jpg:
a) Vcc → R → not-A
b) Vcc → R → Q → ground
c) A → R → Q → not-A
d) A → R → Q → ground
I don't get why the current can't go by the (a) route as well as it goes through the transistor Q (case b)?
Both circuits (a) and (b) have the same resistance with R. So, what's going on in this logical NOT-element that makes this scheme works correctly?
I presume, while not being sure, the transistor Q amplifies the current in the circuit (b), so the circuit (a) receives almost 0 Amperes due to the law of Om.
en.m.wikipedia.org/wiki/Inverter_(logic_gate)#/media/File%3ARTL_NOT_Gate.svg
I don't know whether this analysis is correct, but I've made it in two conceptual views:
* there are three circuits:
a) V5+ °——— ———°V?
b) V5+ °——— ——.\_._/Q ———° V0
c) V5+ °——— ———|<→Q ———° V?
d) V5+ °——— ———|< Q ————° V0
or as it is on the jpg:
a) Vcc → R → not-A
b) Vcc → R → Q → ground
c) A → R → Q → not-A
d) A → R → Q → ground
I don't get why the current can't go by the (a) route as well as it goes through the transistor Q (case b)?
Both circuits (a) and (b) have the same resistance with R. So, what's going on in this logical NOT-element that makes this scheme works correctly?
I presume, while not being sure, the transistor Q amplifies the current in the circuit (b), so the circuit (a) receives almost 0 Amperes due to the law of Om.